1.Let the Second number = X Now, the first number = 2X (since first number is twice the second number) The third number = (X+2X)+ 4 = 3X +4 (third number is 4 times more than the sum of the first two) The fourth number = 2X-X -3 = x-3(since it is 3 less than the difference of the first two numbers) And finally we have the sum of all the numbers = 92 i.e. X+2X+3X +4 +X-3 =92 7x = 92-1 7x = 91 OR X = 13