Answer:
[tex]\frac{7(a-7)}{(a+8)(a-8)}[/tex]
Step-by-step explanation:
we have
[tex]\frac{7}{a+8}+\frac{7}{a^{2}-64}[/tex]
Remember that
[tex]a^{2}-64=(a+8)(a-8)[/tex]
substitute
[tex]\frac{7}{a+8}+\frac{7}{(a+8)(a-8)}=\frac{7(a-8)+7}{(a+8)(a-8)}\\ \\=\frac{7a-56+7}{(a+8)(a-8)}\\ \\= \frac{7a-49}{(a+8)(a-8)}\\ \\=\frac{7(a-7)}{(a+8)(a-8)}[/tex]