makylab26 makylab26

09-04-2018
Mathematics

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x^4 + 2x^3 + 4x + 8 / x + 2

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Аноним Аноним

09-04-2018

[tex] \dfrac{x^4 + 2x^3 + 4x + 8}{x + 2} [/tex]

[tex]= \dfrac{x^3(x + 2) + 4(x + 2)}{x + 2} [/tex]

[tex]= \dfrac{(x + 2)(x^3+4) }{x + 2} [/tex]

[tex]= x^3 + 4[/tex]

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