Balance Chemical Equation, 2 CO + O₂ → 2CO₂ Acc. to this reaction, 88 g (2 mole) of CO₂ was produced when = 56 g (2 mole)of CO was reacted So, 24.7 g of CO₂ will be produced by reacting = X g of CO
Solving for X, X = (56 g × 24.7 g) ÷ 88 g
X = 2.26 g ÷ 88 g
X = 0.0257 g of CO
Result: 0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.