joseluis2502
joseluis2502 joseluis2502
  • 10-03-2018
  • Mathematics
contestada

The points (j, - 8) and (1, - 2) fall on a line with a slope of - 6. What is the value of j?

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Louli
Louli Louli
  • 10-03-2018
Answer:
j = 2

Explanation:
Slope of the line can be calculated using the following rule:
slope = [tex] \frac{y2-y1}{x2-x1} [/tex]

We are given:
slope = -6
point (j,-8) representing (x1,y1)
point (1,-2) representing (x2,y2)

Substitute with the givens in the above equation and solve for j as follows:
slope = [tex] \frac{y2-y1}{x2-x1} [/tex]
-6 = [tex] \frac{-2-(-8)}{1-j} [/tex]
-6(1-j) = -2-(-8)
-6 + 6j = 6
6j = 6+6 = 12
j = 12/6
j = 2

Hope this helps :)
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