sammuelanderson5522 sammuelanderson5522

09-03-2018
Chemistry

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An aqueous solution contains 0.100 m naoh at 25.0 °c. the ph of the solution is ________.

Respuesta :

20-03-2018

Recall; pH + pOH = 14
In this case [OH-] =0.100 m
therefore;
pOH = -LOG[OH-]
= - Log (0.100)
= 1.00
Therefore; the pOH is 1.00
And since, pH +pOH = 14
Then pH = 14-pOH
= 14 -1
= 13
Thus the pH is 13.00

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