Respuesta :

[tex]\bf \sqrt{5x-7}=\sqrt{3x+5}\impliedby \textit{squaring both sides} \\\\\\ (\sqrt{5x-7})^2=(\sqrt{3x+5})^2\implies 5x-7=3x+5\implies 2x=12 \\\\\\ x=\cfrac{12}{2}\implies x=6[/tex]

x=6 loves because it just does

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