kitkatplaysg kitkatplaysg
  • 08-02-2018
  • Mathematics
contestada

T = 2π √l/g Re-arrange to make l the subject.

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sqdancefan
sqdancefan sqdancefan
  • 08-02-2018
[tex] T = 2 \pi \sqrt{ \frac{l}{g}} [/tex]
[tex] \frac{T}{2 \pi} = \sqrt{ \frac{l}{g}} [/tex]
[tex] ( \frac{T}{2 \pi} )^{2} = \frac{l}{g} [/tex]
[tex] l = g \times ( \frac{T}{2 \pi} )^{2} [/tex]
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