bubbly1054
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Review this equation: HCl + NaOH NaCl + H2O. What volume of a 6.0 M HCl solution is required to completely neutralize 125.0 ml of a 2.5 M NaOH solution?

125 ml
2.5 ml
52 ml
6.0 ml
104 ml

Respuesta :

Erudite1
To find the volume of acid used, the following formula apply: CAVA =CBVB, 
Where: CA = Concentration of acid = 6.0M
VA = Volume of acid used =?
CB = Concentration of base = 2.5M
VB = Volume of base = 125 ml
To find VA, make VA the subject of the formula:
VA = CBVB/ CA
VA = [2.5 * 125] / 6.0 = 312.5 / 6 = 52.08
Therefore, the Volume of the acid use is 52 ml.
The correct answer is C.
lovehurt6474
moles of NaOH = 125 ml * 2.5mol/L = 312.5 m moles the same number of moles, of HCl must be the same but notice we have not given the volume, but the molarity, so the moles must be 312.5 m mole so M.V = 312.5 6V = 312.5 V = 52.08 ml