A 52.8-g sample of glucose (a nondissociated, nonvolatile solute with the formula C6H12O6) is dissolved in 158.0 g of water. What is the vapor pressure of this solution at 100°C?
calculate the mole of glucose and water The moles of water =158g/18g/mol=8.778 moles moles of glucose =52.8g/180g/mol=0.293 moles determine the mole fraction of the solvent that is x solvent = 8.778/ (8.778+0.293)=0.9677 use the Raults law to determine the vapor pressure 100 degree of water has a vapor pressure of 760 mmhg p solution=(x solvent) (p^o solvent) p solution=0.9677 x760 =735.45 mmHg