domie7140 domie7140
  • 08-12-2017
  • Physics
contestada

Find the peak electric field 1.3 m from a 60-w lightbulb that radiates equally in all directions.

Respuesta :

shinmin
shinmin shinmin
  • 18-12-2017
To answer the problem we would be using this formula which is I(peak) = P(peak)/(4πd^2) = 4.24413181578388 w/m^2 
E = sqrt(I(peak)*Z0) = 39.9861614728793 V/m 
B = µ0*sqrt(I(peak)/Z0) = 1.33379477721328E-7 T 
(Free-space impedance Z0 = sqrt(µ0/e0) = 376.730313462204 ohms)
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