falcon9837
falcon9837 falcon9837
  • 14-11-2017
  • Mathematics
contestada

What is the solution of the system?


Use the elimination method.

{−4x−2y=−12
{2x+4y=−12

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sqdancefan
sqdancefan sqdancefan
  • 26-08-2018

Divide the first equation by 2 and add the result to the second equation. This will eliminate x.

... (-4x -2y)/2 + (2x +4y) = (-12)/2 +(-12)

... 3y = -18 . . . . . collect terms

... y = -6 . . . . . . . divide by 3

Substitute this into either equation to find x. Let's use the second equation, where the coefficient of x is positive.

... 2x +4(-6) = -12

... 2x = 12 . . . . . . . . add 24

... x = 6 . . . . . . . . . . divide by 2

The solution is (x, y) = (6, -6).

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