romero8197 romero8197
  • 07-10-2015
  • Mathematics
contestada

what is the inverse one to one function of f(x) = square root of x-2???

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Panoyin
Panoyin Panoyin
  • 08-10-2015
[tex]f(x) = \sqrt{x - 2} \\y = \sqrt{x - 2} \\y^{2} = (\sqrt{x - 2})^{2} \\y^{2} = x - 2 \\x^{2} = y - 2 \\x^{2} + 2 = y \\x^{2} + 2 = f^{-1}(x)[/tex]
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