Respuesta :

blanchellite
[tex] a^{-n} = \frac{1}{ a^{n} } [/tex]
So, [tex]4-2( 4^{-2})=4-2 \frac{1}{ 4^{2} } = 4-2 \frac{1}{16} = 4- \frac{1}{8} [/tex]
We amplify 4 with 8 and we get:
[tex] \frac{32-1}{8} = \frac{31}{8}= 3,875 [/tex]