Respuesta :

Abu99
[tex]f(x) = x^{2} - 3x + 3 \\ g(x) = \frac{x - 1}{4} \\ g(5) = \frac{(5) - 1}{4} = 1 \\ f(1) = (1)^{2} - 3(1) + 3 = 1 \\ Therfore, f(g(5)) = 1[/tex]