koyaldev108 koyaldev108
  • 06-01-2024
  • Mathematics
contestada

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Respuesta :

georgepahno georgepahno
  • 06-01-2024

Answer:

x² - 5x + 3 = 0

x = (5 ± √((-5)² - 4(1)(3)))/2

= (5 ± √(25 - 12))/2

= (5 ± √13)/2

2(5 + √13)/((5 - √13)(5 + √13)) =

2(5 + √13)/12 = (5 + √13)/6

2(5 - √13)/((5 - √13)(5 + √13)) =

2(5 - √13)/12 = (5 - √13)/6

(x - (5/6 + (1/6)√13))(x - (5/6 - (1/6)√13)) = 0

((x - 5/6) - (1/6)√13)((x - 5/6) + (1/6)√13) = 0

(x - 5/6)² - (13/36) = 0

x² - (5/3)x + 25/36 - 13/36 = 0

x² - (5/3)x - 1/3 = 0

3x² - 5x - 1 = 0

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