Respuesta :

mariamikayla
[tex]x^2+4x+3=0 \\\\ x^2+x+3x+3=0 \\\\ x(x+1)+3(x+1)=0 \\\\ (x+1)(x+3)=0 \\\\\\ x+1=0 \ \ \Longrightarrow \boxed{x=-1} \\\\ x+3=0 \ \ \Longrightarrow \boxed{x=-3}[/tex]
Panoyin
x² + 4x + 3 = 0
x² + 3x + x + 3 = 0
(x + 1)(x + 3) = 0
x + 1 = 0  or  x + 3 = 0
    - 1  - 1          - 3  - 3
      x = -1            x = -3