Respuesta :
[tex]\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\qquad
\begin{cases}
r=radius\\
h=height\\
-------\\
V=256\\
h=16
\end{cases}\implies 256=\cfrac{\pi \cdot r^2\cdot 16}{3}[/tex]
solve for "r"
solve for "r"
