justxlea justxlea
  • 07-03-2017
  • Mathematics
contestada

factorization of x3+8

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Аноним Аноним
  • 07-03-2017
I hope this helps you



x^3+2^3



(x+2)(x^2-2x+4)
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FelisFelis FelisFelis
  • 19-06-2019

Answer:

The factor of [tex]x^{3}+8[/tex] is [tex](x+2)(x^{2}-2x+4)[/tex]

Step-by-step explanation:

We need to factorise the given expression [tex]x^{3}+8[/tex]

Re-write the expression [tex]x^{3}+8[/tex] as:

[tex]x^{3}+2^{3}[/tex]

Since, [tex]a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2})[/tex]

so, here a = x and b = 2

[tex](x+2)(x^{2}-2x+2^{2})[/tex]

[tex](x+2)(x^{2}-2x+4)[/tex]

Hence, The factor of [tex]x^{3}+8[/tex] is [tex](x+2)(x^{2}-2x+4)[/tex]

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