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Given that a bag of M & Ms has 21 brown candies, 15 orange candies, 10 yellow candies, 14 red candies, and 5 green candies, find the following probabilities. Enter all answers as reduced fraction. Do not use any spaces in your answers. What is the probability of choosing a red M & M, putting it back, and then choosing a brown M & M?

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Based on the number of candies, the probability of choosing a red M & M is 21.5%. The probability of choosing a brown M & M would be 32.3%.

What is the probability?

First, find the number of candies in total:

= 21 + 15 + 10 + 14 + 5

= 65 candies

Probability of picking a red M & M:

= 14 red candies / 65 total

= 21.5%

The probability of picking a brown M & M after putting the red back is:

= 21 brown candies / 65 total

= 32.3%

Find out more on probability at https://brainly.com/question/24299308

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