Livebug123
Livebug123 Livebug123
  • 09-02-2017
  • Mathematics
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How many different 4 person subcommittes can be formed from a club having 12 members

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claymia1
claymia1 claymia1
  • 09-02-2017
12C4 = (12!)/[(12 - 4)!4!] = (12!)/(8!4!) = (12 x 11 x 10 x 9 x 8!)/(8! x 4 x 3 x 2 x 1) Simplify 8! with 8!, 12 with 4 x 3, 10 with 2 = 11 x 5 x 9 = 495
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