Question :
- What is the equivalent resistance of a circuit that contains three 10.0 Ω resistors connected in series to a 6.0 V battery?
Options given :
- A. 0.600 Ω
- Β. 60.0 Ω
- C. 16.0 Ω
- D. 30.0 Ω
Solution :
As we know that,
When a circuit is connected in series resistance is calculated by :
- Rs = R1 + R2 + R3 .... Rn
Here,
As a circuit contains three resistors. So R1 , R2 and R3 would be :
- R1 = 10 Ω
- R2 = 10 Ω
- R3 = 10 Ω
Now,
>> Rs = 10 + 10 + 10
>> Rs = 30 Ω
Therefore,
