The amount spent on an advertisement that will result in maximum profit is $40,000 and that maximum profit is $5,450,000.
a) The maximum profit of the company occurs when the first derivative of the profit function is equal to zero as follows:
p’(x) = -10x + 400 = 0
b) The amount spent on an advertisement that will result in the maximum profit can be calculated from the maximum profit function as follows:
-10x + 400 = 0
x = -400 / -10
x = 40 in thousand dollars
Substituting x = 40 into the profit function, we have:
p(x) = (-5 * 40²) + (400 * 40) – 2550 = 5,450 in thousand dollars
Explanation: The calculation above implies that the amount spent on an advertisement that will result in the maximum profit is $40,000 and that the maximum profit is $5,450,000.
c) To calculate the amount that must be spent on advertising to obtain a profit of at least $54,000,000 (or 54,000 in thousand dollars), we equate it to the profit function and solve for x as follows:
54,000 = -5x²+400x-2550
54,000 + 2,550 = -5x²+400x
56,550 = -5x²+400x
5x² - 400x + 56,550 = 0 .................................. (1)
Using the almighty formula as follows:
x = (-b +/- (b^2 - 4ac)^0.5) / 2a ...................... (2)
Where, from equations (1) & (2), we have:
a = 5
b = -400
c = 56,550
Substituting the values into equation (2), we have:
x = (-(-400) +/- (-400^2 - (4 * 5 * 56,550))^0.5) / (2 * 5)
x = Undefined
Since x = undefined, this implies that there is no unique solution to this problem.
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