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Answer:

  • 12 and 3

Explanation:

Let the integers be x and y

Their sum:

  • x + y = 15

rewrite

  • x = 15 - y

Their product:

  • (x)(y) = 36

rewrite

  • x = 36/y

Solving simultaneously:

  • 36/y = 15 - y
  • 36 = 15y - y²
  • y² - 15y + 36 = 0
  • (y - 12)(y - 3) = 0
  • y = 12, 3

X values:

  • when x = 12, y = 3
  • when x = 3, y = 12

The integers are 12 and 3

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