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During radioactive beta-decay, a neutron (1.6749x10-27 kg) at rest decays into a very slow moving proton (1.6726x10-27 kg) and a fast electron (9.109x10-31 kg). What is the speed of the electron? (Hint: find the total energy of the electron)

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onyebuchinnaji

The speed of the electron emitted in the radioactive beta-decay is determined as 2.186 x 10⁶ m/s.

Speed of electron

The speed of the electron is determined from the total energy of the electron.

Assuming the emitted electrons are in first energy level, E = 13.6 eV

K.E = ¹/₂mv²

v² = 2K.E/m

v² = (2 x 13.6 x 1.6 x 10⁻¹⁹)/(9.11 x 10⁻³¹)

v² = 4.777 x 10⁻¹²

v = 2.186 x 10⁶ m/s

Learn more about speed of electrons here: https://brainly.com/question/12889606

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