Answer:
B.2106π mm^3
Step-by-step explanation:
here is the volume of a drill
[tex]\pi \: {r}^{2} h \: + \frac{1}{3} \pi \: {r}^{2} h[/tex]
[tex]\pi \times 81 \times 18 + \frac{1}{3} \times \pi \times 81 \times 24[/tex]
[tex] > > > 2106 \pi \: {mm}^{3} [/tex]
