Answer:
given :-
for rectangular part: length=12in, breadth=8in
for triangular part:base=8in, height=3in
area of the given fig:
area of the given fig:area of 2 triangles +area of rectangle
[tex]→2( \frac{1}{2} \times b \times h) + l \times b \\ →2( \frac{1}{2} \times 8 \times 3) + 12 \times 8 \\ →24 + 96 \\ → {120in}^{2} [/tex]
hope it helps you<3
