Answer:
x=1 and x=-1/3
Step-by-step explanation:
[tex]3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}[/tex]
[tex]x-\frac{1}{3}=\frac{2}{3}\\ \\x=\frac{3}{3}\\ \\x=1[/tex]
[tex]x-\frac{1}{3}=-\frac{2}{3}\\ \\x=-\frac{1}{3}[/tex]
Therefore, x=1 and x=-1/3
