09-12-2021
Chemistry

contestada

How many atoms of lead are present in 78.40 grams of lead?

Respuesta :

11-12-2021

mole = 78.40/207.2

= 0.379 mol

1 mol = 6.02 × 10^23 atoms

0.379 mol = X

X = 0.379/1 × 6.02 × 10^23

= 6.296 × 10^-25 atoms

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