babyyodakins babyyodakins
  • 09-11-2021
  • Mathematics
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How do I prove ABCD to be a rectangle

How do I prove ABCD to be a rectangle class=

Respuesta :

lynnkc2000 lynnkc2000
  • 09-11-2021

Answer:

steps below

Step-by-step explanation:

AB = DC, AE=DE, ∠BAE = ∠CDE = 90°

ΔBAE ≅ ΔCDE   (SAS)

BE = CE   .. corresponding sides of congruent triangles

∠EBC = ∠ECB  ... base angles of isosceles triangle

∠ABC = ∠ABE + ∠EBC = ∠DCE + ∠ECB = ∠DCB

∠ABC + ∠DCB = 360° - ∠CDE - ∠BAE = 360° - 180° = 180°

∠ABC = ∠ DCB = 1/2 * 180° = 90°

∴ ABCD is rectangle

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