Answer:
245
Step-by-step explanation:
To find the value of a function at a specific point you can substitute that point into the equation.
For the function [tex]f(x)=\frac{1}{5}(3-x)^{2}[/tex], the specific point would be substituted in for every x in the equation.
[tex]f(-32)=\frac{1}{5} (3-(-32))^{2}=\frac{1}{5}(35)^{2}=\frac{1225}{5}=245[/tex]
