Answer:
a. 3.4m
b. 12.2m
Step-by-step explanation:
SOH CAH TOA
[tex]Sin QPS=\frac{Opposite}{hypotenuse}[/tex]
sin 15° = [tex]\frac{QS}{PQ}[/tex]
QS= sin 15° * PQ
QS = 0.2588 * 12.6 = 3.36088 ≈ 3.4m
a. The length of QS = 3.4m
b. [tex]cos QPS=\frac{Adjacent}{Hypotenuse}[/tex]
Cos 15° = [tex]\frac{PS}{PQ}[/tex]
PS = Cos 15° * PQ
PS = O.9659 * 12.6 = 12. 17034 ≈ 12.2m
The length of PS = 12.2m
