reyesalejandro99 reyesalejandro99
  • 06-11-2021
  • Chemistry
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8 Fe + S8 → 8 FeS, how many moles of iron (Fe) are needed to react with 8.49 moles of sulfur (S8)?

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JoshEast
JoshEast JoshEast
  • 06-11-2021

Answer: 67.92 moles

Explanation:

Based on the balanced equation, the mole ratio of Iron to Sulphur is 8 to 1.

This means that for every mole of sulfur, 8 moles of iron is needed for the reaction.

∴ since the moles of Sulfur = 8.49 moles

                 ⇒ moles of Iron = 8.49 moles × 8

                                            = 67.92 moles

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