silwal12 silwal12
  • 06-09-2021
  • Mathematics
contestada

lim x tends to a now find x^1/3-a^1/3/x^1/2-a^1/2

Respuesta :

et762572
et762572 et762572
  • 09-09-2021

Answer: [tex]\frac{a}{3}-\frac{2}{3}-\frac{a}{2}[/tex]

Step-by-step explanation:

[tex]\lim _{x\to \:a}\left(\frac{x^1}{3}-\frac{\frac{a^1}{3}}{\frac{x^1}{2}}-\frac{a^1}{2}\right)[/tex]

[tex]=\frac{a^1}{3}-\frac{\frac{a^1}{3}}{\frac{a^1}{2}}-\frac{a^1}{2}[/tex]

[tex]=\frac{a}{3}-\frac{2}{3}-\frac{a}{2}[/tex]

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