kayleonm24 kayleonm24
  • 09-07-2021
  • Mathematics
contestada

please help with this problem!

please help with this problem class=

Respuesta :

shjhshds shjhshds
  • 09-07-2021

Answer:

Second option

Step-by-step explanation:

Let's assume that x is 1 and y is 3

a) [tex]\frac{1}{2}[/tex] < [tex]\frac{3}{2}[/tex] = true

b) -1 < -3 = false

c) 1+2 < 3+2 = true

d) 2 x 1 < 2 x 3 = true

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