vahehehehehhehe vahehehehehhehe
  • 09-06-2021
  • Mathematics
contestada

Please help quickly I really don’t understand this question and i’m freaking out.

Please help quickly I really dont understand this question and im freaking out class=

Respuesta :

Аноним Аноним
  • 09-06-2021

Answer:

[tex] \frac{4 \sqrt{3x} }{9} [/tex]

Step-by-step explanation:

[tex] \frac{4 \sqrt{ {21x}^{2} } }{3 \sqrt{63x} } [/tex]

[tex] \frac{4 \sqrt{ \frac{21 {x}^{2} }{63x} } }{3} [/tex]

[tex] \frac{4 \sqrt{ \frac{x}{3} } }{3} [/tex]

[tex] \frac{4 \sqrt{ \frac{x \times 3}{3} } }{3} [/tex]

[tex] \frac{\frac{4 \sqrt{3x} }{3} }{3} [/tex]

[tex] \frac{4 \sqrt{3x} }{3} \times \frac{1}{3} [/tex]

[tex] \frac{4 \sqrt{3x} }{9} [/tex]

Hope it is helpful...

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