Answer:
2.6 mol HCl
Explanation:
Step 1: Write the balanced equation
2 KMnO₄ + 8 HCl ⇒ 3 Cl₂ + 2 MnO₂ + 4 H₂O + 2 KCl
Step 2: Calculate the number of moles of hydrochloric acid needed to react with 0.64 moles of potassium permanganate.
According to the balanced equation, the molar ratio of KMnO₄ to HCl is 2:8.
0.64 mol KMnO₄ × 8 mol HCl/2 mol KMnO₄ = 2.6 mol HCl
