Answer:
13,456
Step-by-step explanation:
Tn= a+(n-1)d
a is the first term, n is the given number and d is the common difference. d is given by subtracting the first term from the second term or the second from the third. Therefore the the 59th term of the sequence 29, 37, 45 is,
Tn= 29+(59-1)8
=29(58)8
=13,456
