Answer:
vertex point at (-2|11)
f(x)=-2*((x+2)^2+1*-11/2) (simplified)
Step-by-step explanation:
f(x)=-2*x^2+-8*x+3
f(x)=-2*(x^2+4*x+-3/2) ( Factor out )
f(x)=-2*(x^2+4*x+(2)^2+-1*(2)^2+-3/2) ( Complete the square )
f(x)=-2*((x+2)^2+-1*(2)^2+-3/2) ( Use the binomial formula )
hope this helped, I didn't get much to work with so if i'm wrong i'm sorry
