Respuesta :

lak521

Answer:

2 NaI (aq) + Br2 (aq) → 2 NaBr (aq) + I2 (s)

This is an oxidation-reduction (redox) reaction:

2 Br0 + 2 e- → 2 Br-I

(reduction)

2 I-I - 2 e- → 2 I0

(oxidation)
The answer is the first one

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