Answer: 11
Step-by-step explanation:
Given
The second term of an AP is 7
The sixth term of an AP is 23
Suppose a and d be the first term and common difference of the sequence
[tex]\Rightarrow 7=a+d\quad \ldots(i)\\\Rightarrow 23=a+5d\quad \ldots(ii)[/tex]
Subtract the above equations
[tex]\Rightarrow 23-7=5d-d\\\Rightarrow 16=4d\\\Rightarrow d=4[/tex]
Put d in equation (i)
[tex]\Rightarrow 7=a+4\\\Rightarrow a=3[/tex]
So, the third term of the AP is [tex]a+2d[/tex]
[tex]\Rightarrow 3+2\times 4=11[/tex]
