rebekamata
rebekamata rebekamata
  • 10-04-2021
  • Mathematics
contestada

find the inverse of h(x)= -x^5+2 step by step

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leena
leena leena
  • 10-04-2021

Hi there!

[tex]\large\boxed{y = \sqrt[5]{-(x-2)}}[/tex]

[tex]h(x) = -x^{5} + 2[/tex]

Rewrite h(x) as y:

[tex]y = -x^5 + 2[/tex]

Switch the x and y variables:

[tex]x = -y^{5} + 2[/tex]

Isolate y by subtracting 2 from both sides:

[tex]x - 2 = -y^5[/tex]

Multiply both sides by -1:

[tex]-(x-2) = y^5[/tex]

Take the 5th root of both sides:

[tex]y = \sqrt[5]{-(x-2)}[/tex]

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