kkpalos2022 kkpalos2022
  • 09-04-2021
  • Mathematics
contestada

If the length of a rectangle is 12 times the width and the area is 48 square feet, what are the
dimensions?

Respuesta :

devishri1977
devishri1977 devishri1977
  • 11-04-2021

Answer:

dimensions are 2 ft, 24ft

Step-by-step explanation:

width = w

length = 12w

Area of rectangle = 48 square feet

length * width = 48

12w * w = 48

12w² = 48           {Divide both side by 12}

w² = 48/12

w² = 4 =2²

w =2 ft

l = 12*2 = 24ft

Answer Link
Аноним Аноним
  • 12-04-2021

Answer:

Solution :-

Let the width be w and Length will be 12w

So,

Area = lw

48 = 12w × w

48/12 = w²

4 = w²

√4 = √w²

2 = 2

Length = 12(2) = 24 cm

Breadth = 2 cm

[tex] \\ [/tex]

Answer Link

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