Answer: 14 , 6
Step-by-step explanation:
Given
2 hammers and a screwdriver cost 34
1 hammer and 3 screwdrivers cost 32
Suppose the cost of the hammer is x and the cost of the screwdriver is y
[tex]\therefore 2x+y=34\quad\ \ldots(i)\\x+3y=32\quad \ldots(ii)[/tex]
Solving (i) and (ii) we get
[tex]x=14;y=6[/tex]
Thus, hammer cost 14 and screwdriver costs 6
