Square ABCD has sides of length 15 ft. If the remaining part of the shape is a semicircle, what is the perimeter around the entire shape, to the nearest hundred?

A) 53.41 ft
B) 58.27 ft
C) 61.28 ft
D) 68.55 ft

Respuesta :

Answer:

68.55

Step-by-step explanation:

C= 2πr

C=2 x 3.14 x 7.5 = 47.1 (Divide by 2 for half circle)

47.1 ÷ 2 = 23.55 + 15 + 15 + 15 = 68.55