Answer:
Y when X=36 and Z=2 is 90
Step-by-step explanation:
Given -
Y varies directly as X and inversely as the square of Z
[tex]y = \frac{kx}{z^2}\\30 = \frac{k *75}{5^2} \\30 = 75k/25[/tex]
[tex]k = 10[/tex]
As we know
[tex]y = \frac{kx}{z^2}[/tex]
Substituting value of X = 36 and Z = 2 in above equation, we get -
[tex]y = \frac{10*36}{2*2} \\y = 90[/tex]
