madisun2004 madisun2004

08-03-2021
Mathematics

contestada

factor w^4x^2y^3−w^2x^2y WITHOUT using grouping

Respuesta :

idontlikeschool321 idontlikeschool321

08-03-2021

Answer:

w^2x^2y * (wy-1)*(wy+1)

Step-by-step explanation:

hope this helps!

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