Respuesta :

Answer:

(a+bi)×(b+ai)

=>ab+a²i+b²i+abi²

=> ab+(-1)ab+(a²+b²)i

=>(a²+b²)i

so we can say it is purely imaginary number

hope it helped!

qpcnbm

Answer:

(a+bi)×(b+ai)

=>ab+a²i+b²i+abi²

=> ab+(-1)ab+(a²+b²)i

=>(a²+b²)i

Step-by-step explanation: