Answer:
305.88 g
Explanation:
4 Al + 3 O₂ → 2 Al₂O₃
First, we convert 6 moles of aluminum (Al) into moles of aluminum oxide (Al₂O₃), using the stoichiometric coefficients:
6 mol Al * [tex]\frac{2molAl_2O_3}{4molAl}[/tex] = 3 mol Al₂O₃
Finally we convert 3 moles of aluminum oxide into grams, using its molar mass:
3 mol Al₂O₃ * 101.96 g/mol = 305.88 g
