Kat2inyssopkristu4la Kat2inyssopkristu4la

08-11-2016
Mathematics

contestada

]Find the value of n such that x^2-10x+n is a perfect square trinomial.

A) 50
B) 25
C) -5
D)100

Respuesta :

Аноним Аноним

08-11-2016

I hope this helps you

x.x-2.5.x+n

(x-5)(x-5)

(x-5)^2

n= -5

Answer Link

Edufirst Edufirst

11-11-2016

x^2 - 10x + [10/2]^2 = x^2 -10x +5^2 = (x -5)^2 = x^2 -10x + 25

Then n = 25.

Answer: option B) 25

Answer Link

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